The theory of functions of a complex variable is the most important in solving a large number of Engineering and Science problems. Many complicated integrals of real functions are solved with the help of a complex variable.
UNIT-III
ANALYTIC FUNCTIONS
Analytic
functions - Necessary and sufficient conditions for analyticity in Cartesian
and polar co-ordinates - Properties - Harmonic conjugates - Construction of
analytic function - Conformal mapping - Mapping by functions w z + c, cz, 1/z,
z2 - Bilinear transformation.
INTRODUCTION
The
theory of functions of a complex variable is the most important in solving a
large number of Engineering and Science problems. Many complicated integrals of
real functions are solved with the help of a complex variable.
(a) Complex variable :
x
+ iy is a complex variable and it is denoted by z.
i.e.,
z = x + iy where i = √-1
(b) Function of a complex variable
If
z = x + iy and w = u + iv are two complex variables, and if for each value of z
in a given region R of the complex plane there corresponds one or more values
of w, then w is said to be a function of z and is denoted by w = f(z) = f(x +
iy) u (x, y) + iv (x, y) where u (x, y) and v (x, y) are real functions of the
real variables x and y.
Note
(i) Single-valued function :
If
for each value of z in R there is correspondingly only one value of w, then w
is called a single valued function of z.
Example:
w = z2, w = 1/z
Note
(ii) Multiple - valued function
If
there is more than one value of w corresponding to a given value of z, then w
is called a multiple - valued function.
Example:
w = z1/2
Note
(iii) The distance between two points z
and
zo is | z - zo |
Note
(iv)
The circle C of radius δ with centre at the point zo can be
represented by
|
z - zo | = δ
Note
(v) |
z - zo | δ represents the interior of the circle excluding its
circumference.
Note
(vi) | z - zo | ≤ δ represents the interior of
the circle including its circumference
Note
(vii) | z - zo | > δ represents the
exterior of the circle
Note
(viii) A circle of radius 1 with centre at origin can be
represented by | z | = 1
(c) Neighbourhood of a point zo
Neighbourhood
of a point zo we mean a sufficiently small circular region [
excluding the points on the boundary with centre at zo
i.e.,
| z - zo | < δ
(d) Limit of a Function
Let
f (z) be a single valued function defined at all points in some neighbourhood
of point zo.
Then
the limit of f (z) as z approaches zo is wo
(e) Continuity
If
f (z) is said to be continuous at z = zo, then
Note
(ix)
If two functions are continuous at a point their sum, difference and product
are also continuous at that point, their quotient is also continuous at any
such point [dr ≠ 0]
Example
3.0.1 State the basic difference between the limit of a function of a real
variable and that of a complex variable. [A.U M/J 2012]
Solution
:
In
real variable, x→xo implies that x approaches xo along the X-axis
(or) a line parallel to the X-axis.
In
complex variables, z → zo implies that z approaches zo along any
path joining the points z and z0 that lie in the z-plane.
(f) Differentiability at a point
A
function f (z) is said to be differentiable at a point z = zo, if
the limit
This
limit is called the derivative of f (z) at the point z = zo
Note
(x).
If f (z) is differentiable at zo, then f(z) is continuous at Zo.
This is the necessary condition for differentiability.
Example
3.0.2 If f (z) is differentiable at zo, then show that it is continuous at that
point.
Solution
:
As
f (z) is differentiable at zo both f (z0) and f' (z0)
exist finitely.
This
is exactly the statement of continuity of f (z) at z0.
Example
3.0.3. Give an example to show that continuity of a function at a point does
not imply the existence of derivative at that point.
Solution
:
Consider
the function w= | z |2 = x2 + y2
This
function is continuous at every point in the plane, being a continuous function
of two real variables. However, this is not differentiable at any point other
than origin.
Example
3.0.4. Show that the function f (z) is discontinuous at z = 0, given that when z ≠ 0 and f (0) = 0.
Solution:
Example
3.0.5. Show that the function f(z) is discontinuous at the origin (z = 0),
given that f(z) = xy (x-2y) / x3
+ y3 when z ≠ 0
=
0, when z = 0.
Solution
:
Probability and complex function: Unit III: Analytic functions : Tag: : - Analytic functions
Probability and complex function
MA3303 3rd Semester EEE Dept | 2021 Regulation | 3rd Semester EEE Dept 2021 Regulation