Electron Devices and Circuits: Unit IV: Multistage and Differential Amplifiers

D.C. Analysis of Differential Amplifier

• The d.c. analysis means to obtain the operating point values i.e. ICQ and VCEQ for the transistors used. The supply voltages are d.c. while the input signals are a.c., so d.c. equivalent circuit can be obtained simply by reducing the input a.c. signals to zero.

D.C. Analysis of Differential Amplifier

• The d.c. analysis means to obtain the operating point values i.e. ICQ and VCEQ for the transistors used. The supply voltages are d.c. while the input signals are a.c., so d.c. equivalent circuit can be obtained simply by reducing the input a.c. signals to zero. The d.c. equivalent circuit thus obtained is shown in the Fig. 8.7.1. Assuming RS1 = RS2, the source resistance is simply denoted by RS.


• The transistors Q1 and Q2 are matched transistors and hence for such a matched pair we can assume :

i) Both the transistors have the same characteristics.

ii) REI = RE2 hence RE = RE1 || RE2 .

iii) RC1 = RC2 hence denoted as RC.

iv) |VCC| = |VEE| and both are measured with respect to ground.

• As the two transistors are matched and circuit is symmetrical, it is enough to find out operating point ICQ and VCEQ, for any one of the two transistors. The same is applicable for the other transistor.

• Applying KVL to base-emitter loop of the transistor Q1


From the equation (8.7.6), we can observe that

i) RE determines the emitter current of Q1 and Q2 for the known value of VEE

ii) The emitter current through Q1 and Q2 is independent of collector resistance RC.

• Now let us determine VCE. As IE is known and IE IC, we can determine the collector voltage of Q1 as

VC = VCC – IC – IC RC …. (8-7.7)

• Neglecting the drop across RS, we can say that the voltage at the emitter of Qi is approximately equal to -VBE. Hence the collector to emitter voltage is


• Hence IE = IC = ICQ while VCE = VCEQ for given values of VCC andVEE.

Key Point : In the equation (8.7.6), the sign of VEE is already considered to be negative, while deriving it. Hence while using this equation to solve the problem, only the magnitude of VEE should be used and negative sign of VEE should not be used again.

• Thus for both the transistors, we can determine operating point values, using equations (8.7.6) and (8.7.8). With the same biasing arrangement, the d.c. analysis remains same for all the four possible configurations of differential amplifier.


Key Point : The d.c. analysis and expressions for ICQ and VCEQ remain same for all the differential amplifier circuit configurations.

 

Ex. 8.7.1 Calculate the operating point values for the circuit shown in the Fig. 8.7.2.


• The sign of VEE is already considered while deriving the equation hence VEE must be replaced by 12 V. And assume VBE = 0.7 V.



 

Electron Devices and Circuits: Unit IV: Multistage and Differential Amplifiers : Tag: : - D.C. Analysis of Differential Amplifier