Electrical Machines: Unit IV: Single Phase Transformer

Losses in a Transformer

In a transformer, there exists two types of losses. i) The core gets subjected to an alternating flux, causing core losses. ii) The windings carry currents when transformer is loaded, causing copper losses.

Losses in a Transformer

In a transformer, there exists two types of losses.

 i) The core gets subjected to an alternating flux, causing core losses.

ii) The windings carry currents when transformer is loaded, causing copper losses.

1. Core or Iron losses

• Due to alternating flux set up in the magnetic core of the transformer, it undergoes a cycle of magnetisation demagnetisation. Due to hysteresis effect there is loss of energy in this process which is called hysteresis loss.

It is given by, Hysteresis loss = Kh Bm1.67 f v watts

Kh = Hysteresis constant depends on material and

Bm = Maximum flux density

f = Frequency and v = Volume of the core.

• The induced e.m.f. in the core tries to set up eddy currents in the core and hence responsible for the eddy current losses. The eddy current loss is given by,

Eddy current loss = Ke Bm2 f2t2 watts/unit volume

where Ke = Eddy current constant and t = Thickness of the core.

• As seen earlier, the flux in the core is almost constant as supply voltage V1 at rated frequency f is gato always constant. Hence, the flux density Bm in the core and hence both hysteresis and eddy current losses are constants at all the loads. Hence the core or iron losses are also called constant losses. The iron losses are denoted as Pi.

• The iron losses are minimized by using high grade core material like silicon steel having very low hysteresis loop and by manufacturing the core in the form of laminations.

2. Copper losses

• The copper losses are due to the power wasted in the form of I2R loss due to the resistances of the primary and secondary windings. The copper loss depends on the magnitude of the currents flowing how through the windings.

• Total Cu loss = I12 R1 +I22 R2 = I12 (R1 + R'2) = I22 (R2 +R'1) = I12 R1e = I22 R2e

• The copper losses are denoted as PCu. If the current through the windings is full load current, we get copper losses at full load. If the load on transformer is half then we get copper losses at half load which are less than full load copper losses. Thus copper losses are called variable losses.

• Copper losses are proportional to the square of the current and square of the kVA rating as voltage is constant.

 So,  PCu ∞ I2 (kVA)2

Thus for a transformer,

Total losses = Iron losses + Copper losses = Pi + PCu

• The copper losses are kept minimum by designing the windings with low resistance values.

Review Question

1. Explain the various losses in a transformer and how to minimize them? On what factors they depend? Give the equations for these losses.

 

Electrical Machines: Unit IV: Single Phase Transformer : Tag: : - Losses in a Transformer