In a transformer, there exists two types of losses. i) The core gets subjected to an alternating flux, causing core losses. ii) The windings carry currents when transformer is loaded, causing copper losses.
Losses in
a Transformer
In
a transformer, there exists two types of losses.
i) The core gets subjected to an alternating
flux, causing core losses.
ii)
The windings carry currents when transformer is loaded, causing copper losses.
1. Core or Iron losses
•
Due to alternating flux set up in the magnetic core of the transformer, it
undergoes a cycle of magnetisation demagnetisation. Due to hysteresis effect
there is loss of energy in this process which is called hysteresis loss.
It
is given by, Hysteresis loss = Kh Bm1.67 f v
watts
Kh
= Hysteresis constant depends on material and
Bm
= Maximum flux density
f
= Frequency and v = Volume of the core.
•
The induced e.m.f. in the core tries to set up eddy currents in the core and
hence responsible for the eddy current losses. The eddy current loss is given
by,
Eddy
current loss = Ke Bm2 f2t2
watts/unit volume
where
Ke = Eddy current constant and t = Thickness of the core.
•
As seen earlier, the flux in the core is almost constant as supply voltage V1
at rated frequency f is gato always constant. Hence, the flux density Bm in the
core and hence both hysteresis and eddy current losses are constants at all the
loads. Hence the core or iron losses are also called constant losses. The iron
losses are denoted as Pi.
•
The iron losses are minimized by using high grade core material like silicon
steel having very low hysteresis loop and by manufacturing the core in the form
of laminations.
2. Copper losses
•
The copper losses are due to the power wasted in the form of I2R
loss due to the resistances of the primary and secondary windings. The copper
loss depends on the magnitude of the currents flowing how through the windings.
•
Total Cu loss = I12 R1 +I22
R2 = I12 (R1 + R'2) = I22
(R2 +R'1) = I12 R1e = I22
R2e
•
The copper losses are denoted as PCu. If the current through the
windings is full load current, we get copper losses at full load. If the load
on transformer is half then we get copper losses at half load which are less
than full load copper losses. Thus copper losses are called variable losses.
•
Copper losses are proportional to the square of the current and square of the
kVA rating as voltage is constant.
So, PCu
∞ I2 (kVA)2
Thus
for a transformer,
Total
losses = Iron losses + Copper losses = Pi + PCu
•
The copper losses are kept minimum by designing the windings with low
resistance values.
Review Question
1. Explain the
various losses in a transformer and how to minimize them? On what factors they
depend? Give the equations for these losses.
Electrical Machines: Unit IV: Single Phase Transformer : Tag: : - Losses in a Transformer
Electrical Machines I
EE3303 EM 1 3rd Semester EEE Dept | 2021 Regulation | 3rd Semester EEE Dept 2021 Regulation