Operation of Synchronous Motor at Constant Load Variable Excitation

Operation of Synchronous Motor at Constant Load Variable Excitation

In the last article we have seen that when load changes, for constant excitation, current drawn by the motor increases. But if excitation i.e. field current is changed keeping load constant, the synchronous motor reacts by changing its power factor of operation. This is most interesting feature of synchronous motor. Let us see the details of such operation.

Consider a synchronous motor operating at a certain load. The corresponding load angle is δ .

At start, consider normal behaviour of the synchronous motor, where excitation is adjusted to get Eb = V i.e. induced e.m.f. is equal to applied voltage. Such an excitation is called Normal Excitation of the motor. Motor is drawing certain current Ia from the supply and power input to the motor is say P_in. The power factor of the motor is lagging in nature as shown in the Fig. 4.10.1 (a).

Now when excitation is changed, E_b changes but there is hardly any change in the losses of the motor. So the power input also remains same for constant load demanding same power output.

Now  P_in = √3 V_L I_L cosϕ = 3 (V_ph I_aph cos ϕ)

Most of the times, the voltage applied to the motor is constant. Hence for constant power input as V_ph is constant, 'I_aph cos ϕ remains constant.

Key Point So for this entire operation of variable excitation it is necessary to remember that the cosine component of armature current, 'I_a cos ϕ' remains constant.

So motor adjusts its cos ϕ i.e. p.f. nature and value so that Ia cos 0 remains constant when excitation of the motor is changed keeping load constant. This is the reason why synchronous motor reacts by changing its power factor to variable excitation conditions.

1. Under Excitation

When the excitation is adjusted in such a way that the magnitude of induced e.m.f. is less than the applied voltage (E_b < V) the excitation is called Under excitation.

Due to this, E_R increases in magnitude. This means for constant Z_s, current drawn by the motor increases. But E_R phase shifts in such a way that, phasor I_a also shifts (as E_R Λ I_a = θ) to keep I_a cos ϕ component constant. This is shown in the Fig. 4.10.1 (b). So in under excited condition, current drawn by the motor increases. The p.f. cos ϕ decreases and becomes more and more lagging in nature. 

2. Over Excitation

The excitation to the field winding for which the induced e.m.f. becomes greater than applied voltage (E_b > V), is called over excitation.

Due to increased magnitude of E_b' E_R also increases in magnitude. But the phase of E_R also changes. Now E_R Λ I_a = θ is constant, hence I_a also changes its phase. So θ changes. The I_a increases to keep I_a cos constant as shown in Fig. 4.10.1 (c). The phase of E_R changes so that I_a becomes leading with respect to V_ph in over excited condition. So power factor of the motor becomes leading in nature. So overexcited synchronous motor works on leading power factor. So power factor decreases as over excitation increases but it becomes more and more leading in nature.

3. Critical Excitation

When the excitation is changed, the power factor changes. The excitation for which the power factor of the motor is unity (cos ϕ = 1) is called critical excitation. Then I_aph is in phase with V_ph. Now I_a cos ϕ must be constant, cos ϕ = 1 is at its maximum hence motor has to draw minimum current from supply for unity power factor condition.

So for critical excitation, cos ϕ = 1 and current drawn by the motor is minimum compared to current drawn by the motor for various excitation conditions. This is shown in the Fig. 4.10.1 (d).

Review Question

1. Explain the operation of synchronous motor at constant load variable excitation.

AU : May-09, 10, 12, 13, 14, 16,18, Dec.-07, 11, 16, Marks 8