Electron Devices and Circuits: Unit II: (b) Junction Field Effect Transistor (JEET)

The Pinch-off Voltage Vp (JFET)

Solved Example Problems | Junction Field Effect Transistor

A p-type gate is then diffused into the n-type channel. In this device, a slab of n-type semiconductor is sandwiched between two layers of p-type material, forming two p-n junctions.

The Pinch-off Voltage Vp

• The Fig. 3.5.1 shows a single-ended-geometry junction FET. Here, the substrate is of p-type material onto which an n-type channel is epitaxially grown. A p-type gate is then diffused into the n-type channel. In this device, a slab of n-type semiconductor is sandwiched between two layers of p-type material, forming two p-n junctions.


• Let us assume that the p-type region is doped with NA acceptors per cubic meter, n-type region is doped with ND donors per cubic meter and that the junction formed is abrupt.

• We know that, if NA » ND we have Wp « Wn and for the space-charge width, WR(x) = W(x) at a distance x along the channel in Fig. 3.5.2.



where

Ɛ : Dielectric constant of channel material

q : Magnitude of electric charge

VO : Junction contact potential at x

V(x) : Applied potential across space-charge region at x and is a negative number for an applied reverse bias

a - b(x) : Penetration W(x) of depletion region into channel at a point x along channel

• When the drain current is zero, b(x) and V(x) are independent of x and b(x) = b. By substituting b(x) = b = 0 we have

• Now solving for V with assumption |V| <<  |V| we obtain the pinch-off voltage Vp (the diode reverse voltage that removes   all the free charge from the channel) as

|VP| = qND / 2E a2 … (3.5.3)

If we substitute VGS for VO – V(x) and b(x) = b in equation (3.5.1) we get,


From equation (3.5.3) we have

2E / qND = a2 / VP … (3.5.5)

Substituting equation (3.6.5) in equation (3.6.4) we get,


This equation shows that the voltage VGS (the reverse bias across the gate junction) is independent of distance along the channel if ID = 0.

 

Ex. 3.5.1 For an n-channel silicon FET, find the pinch-off voltage and the channel half-width.

Assume : ɑ = 3 × 10-6 m, ND = 1021 electrons/m2, VGS = ½ Vpv ID = 0 and relative dielectric constant of silicon = 12.

Sol. : Since relative dielectric constant of silicon is 12 we have Ɛ = 12 Ɛ0. Using values of q and Ɛ0 we have


 

Ex. 3.5.2 For an n-channel silicon FET with a = 3×l0-4 cm and Nd = 1015 electrons/cm-3. Find (a) the pinch off voltage and (b) the channel half-width for VGS = 0.5 Vp.

AU : June-16, Marks 6

Sol. : a) Note that :

Ɛ0 = 8.85 × 10-14 F/cm

q = 1.6 × 10-19C

Dielectric constant of silicon = 12


 

Ex. 3.5.3 Assume that the p+n junction of a uniformly doped silicon n channel JFET at T = 300 K has doping concentrations of Nɑ = 1018 cm-3 and Nd = 1016 cm-3. Assume that the metallurgical channel thickness a is 0.7 pm Calculate the pinch off voltage. Also calculate pinch-ojf voltage if the metallurgical channel thickness a is 0.75 µm

AU : May-15, Dec.-15, Marks 2

Sol. : Here all quantities are in centimeters instead of meters. Channel thickness a= 0.7 ^ti= 0.7 xlO 4 cm. The internal pinch off voltage is given by


Review Question

1. Derive the expresionfor pinch-off voltage.

AU : Dec.-18

 

Electron Devices and Circuits: Unit II: (b) Junction Field Effect Transistor (JEET) : Tag: : Solved Example Problems | Junction Field Effect Transistor - The Pinch-off Voltage Vp (JFET)