Transmission and Distribution: Unit III: (a) Mechanical Design of Transmission Lines : Two Marks Questions with Answers
Two Marks Questions with
Answers
Q.1 Define sag.
Ans. : When a
conductor is suspended between two points then it takes the shape of parabola
or catenary and sags down.
The difference in levels between the
point of support and the lowest point on the conductor is called sag.
Q.2 What is stringing chart ? What is
its use ?
Ans. : The tension at
the time of erection of a transmission line is given by a cubic equation hence
it is time consuming to solve such equation. Instead of solving such a equation
the graph of tension in kg against the temperature in °C and the graph of sag
in metres against the temperature in °C is obtained. Such graphs are called the
stringing chart.
The stringing chart is very useful to
find the tension and the sag at any temperature and the loading conditions when
these values at any other temperature and the loading conditions are known to
us.
Q.3 What is the effect of wind and ice
loading on sag ?
Ans. : Due to wind
pressure the conductor is subjected to the additional forces acting
horizontally. While due to ice loading the weight of the conductor increases
which acts vertically downwards. Both these factors decide the resultant weight
of the conductor which decides the sag.
Q.4 What is the economical value of span
for 400 kV transmission line ?
AU : May-10
Ans. : The
span must be between 200 m to 400 m. For river and ravine crossings
exceptionally long spans up to 800 m or so is sufficient.
Q.5 Give two factors which affect the
sag in transmission line.
AU : Dec -10, 12,16, May-17
Ans. : The
two important atmospheric factors affecting the sag in transmission line are,
i) Ice coating on the conductor which
increases weight of the conductor
ii) Wind pressure due to which the
conductor gets subjected to the additional forces
Apart from these two factors the span,
weight of the conductors and tension in the conductor also affect the value of
sag.
Q.6 Give the expression of sag when the
supports are at equal level.
Ans. : The
sag is given by, S = (w L2)/(8 T) where w = Weight per unit length
of conductor, L = Length of span and T = Tension in the conductor
Q.7 Define factor of safety.
Ans. : The ultimate
stress which conductor can sustain without fail is called breaking stress. The
normal tension in the conductor is called working stress. The ratio of breaking
stress to the working stress is called the factor of safety denoted as Sf.
Q.8 What is sag template ? What is its
use ?
Ans. : For normal
spans and for standard towers, the sag and the nature of the conductor curve
are calculated under expected load conditions and plotted on a thin stiff
plastic sheet. Such a graph is called sag template.
The sag template can be used for i)
Maintaining safe ground clearance along the entire route of the line ii)
Choosing span and height of towers with good accuracy iii) Positioning the
towers properly iv) Selecting the towers which carry equal loads v) Obtaining overall economical layout of the
system.
Q.9 Which are the types of vibrations
possible in overhead conductors ?
Ans. : The
two types of vibrations possible in overhead conductors in vertical plane are,
i) Aeoline vibrations having frequency range of 8 to 40 Hz with amplitudes
varying from 2 to 5 cm. ii) Galloping or dancing of conductors at the low
frequency and high amplitude.
Q.10 Mention the factors affecting the
conductor vibrations.
Ans. : 1. Atmospheric
conditions such as icing, raining and high winds 2. Span of conductor 3.
Tension in the conductor 4. Types of
clamps used 5. Conductor configuration 6. Height of the towers 7. Number of
dampers
Q.11 Give the minimum ground clearance
required for 33 kV, 66 kV, 110 kV and 220 kV lines.
Ans. : A sufficient
clearance of a conductor from ground under all loading conditions is required
to be maintained for safety. The clearance distance depends on transmission
voltage.
For 33 kV, a clearance of 5.18 m is to
be provided and for every additional 33 kV or for 33 kV line ground clearance
is 5.18 m (17 feet) part thereof, additional 0.3048 m clearance is to be
provided.
For 66 kV, 66 kV = 33 kV + (1 × 33)
Ground clearance = 5.18 + 1 × 0.3048 =
5.4848 m (18 feet)
For 110 kV line
110 kV = 33 kV + 2.33 × 33
Ground clearance = 5.18 + (2.33 ×
0.3048) = 5.89 m (19.32 feet)
For 220 kV line
220 kV = 33 kV + 5.66 × 33
Ground clearance = 5.18 + 5.66 × 0.3048
= 6.90 m (22.63 feet)
Q.12 What is deviation tower ?
Ans. : The
transmission line goes as per available straight paths as far as possible. Due
to unavailability of shortest distance straight corridor, transmission line has
to deviate from its straight way when obstruction comes. The towers used in
such cases to deviate the route of the transmission lines are called deviation
towers or angle towers. The design of such towers is such that they can
withstand large mechanical stress.
Q.13 What is meant by tower spotting ?
Ans. : The art of locating structures of towers in a right way and selecting their type and height so as to meet all the necessary electrical requirements is called tower spotting. The sag template is used for tower spotting.
Transmission and Distribution: Unit III: (a) Mechanical Design of Transmission Lines : Tag: : Transmission and Distribution | Mechanical Design of Transmission Lines - Two Marks Questions with Answers
Transmission and Distribution
EE3401 TD 4th Semester EEE Dept | 2021 Regulation | 4th Semester EEE Dept 2021 Regulation