Physics for Electrical Engineering: Unit II: b. Magnetic Properties of Materials : Anna university solved problems
ANNA UNIVERSITY
SOLVED PROBLEMS
1. A magnetic field strength of 2 ×
105 amperes / metre is applied to a paramagnetic material with a
relative permeability of 1.01. Calculate the values of B and M [A.U.
May 2015]
Given data
Magnetic
field strength H = 2 × 105 A/m
Relative
permeability μr =1.01
Solution
We
know that M/H = μr-1
M
= H (μr -1)
Substituting
the given values, we have
=
2 × 105 (1.01 − 1)
M
= 2 × 103
B
=µ0(M + H)
=
4л × 10-7 (2 × 103 + 2 × 105)
=
4л × 10-7 (0.02 × 105 + 2 × 105)
=
4π × 10-7(2.02 × 105)
B
= 0.2537 Wbm-2
2. Magnetic field intensity of a
paramagnetic material is 104 ampere/metre. At room temperature its susceptibility
is 3.7 × 10-3. Calculate the magnetization of the material.
[A.U. Dec 2014]
Given data
Physics
for Electrical Engineering
Magnetic
field intensity H = 104 ampere / metre
Susceptibility
χ = 3.7 × 10-3
Magnetization
of the material = ?
Solution
We
know that Magnetization = χ Η
Substituting
the given values, we have
=
3.7 × 104
M
= 37 ampere / metre
Physics for Electrical Engineering: Unit II: b. Magnetic Properties of Materials : Tag: : Magnetic Properties of Materials | Physics for Electrical Engineering - Anna university solved problems
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