Engineering Chemistry: Unit IV: b. Combustion of Fuels

Theoretical Calculation of Calorific Values

Dulong's formula with Example Solved Problems

Dulong's formula for the theoretical calculation of calorific value is GCV (or) HCV

THEORETICAL CALCULATION OF CALORIFIC VALUES

Dulong's formula

Dulong's formula for the theoretical calculation of calorific value is

GCV (or) HCV


where C,H,O and S represent the % of the corresponding elements in the fuel.

It is based on the assumption that the calorific values of C, H and S are found to be 8080, 34500 and 2240 kcal, when 1 kg of the fuel is burnt completely. However, all the oxygen in the fuel is assumed to be present in combination with hydrogen in the ratio H : O as 1 : 8 by weight. So the surplus hydrogen available for combustion is H – O/8

NCV (or) L C V = 


1. Problems based on calorific value

Problem 1

Calculate the gross and net calorific values of coal having the following compositions, carbon = 85%, hydrogen = 8%, sulphur = 1%, nitrogen = 2%, ash = 4%, latent heat of steam = 587 cal/gm. (A.U. June 2007)

Solution

(i) Gross calorific value (GCV)


(ii) Net Calorific Value (NCV)

 


Problem 2

Calculate the gross and net calorific values of a coal sample having the following composition C = 80% ; H = 7%; O = 3% ; S = 3.5% ; N = 2.5% and ash 4.4%.

Solution

(i) GCV

(ii) NCV


 

Problem 3

On analysis, a coal sample has the following compositition by weight; C = 85%; O  = 3%; S = 0.5% and ash = 3%. Net calorific was found to be 8400 kcal/kg. Calculate the percentage of hydrogen and gross calorific value of coal.

Solution


 

Problem 4

Calculate the net and gross calorific value of a coal sample having following composition:

C = 82%, H = 8%, O = 5%, N = 1.4% and ash = 3.6%.

Solution

 (i) GCV


 

Problem 5

Calculate the gross and net calorific value of a fuel having following composition 82% C, 8% H, 5% 0, 2.5% S, 1.4% N and 2.1% ash. (APJAKTU, July 2016)

Solution

We know that,

GCV = 1/100 [8080C + 34500 (H – O/8) + 2240S] kcal/kg

= 1/100 [8080 × 82 + 34500 (8 – 5/8) + 2240 × 2.5]

= 9225.97 kcal/kg

NCV = GCV – 0.09H × 587 kcal/kg

NCV = 9225.97 – 0.09 × 8 × 587 = 8803.3 kcal/kg

 

Problem 6

A coal sample has 80% of carbon, 9% of hydrogen, 6% of sulphur and remaining is ash. Calculate the HCV and LCV of the coal sample. (JNTU(H), June 2017)

Solution

(i) Higher Calorific Value (HCV)

(ii) Lower Calorific Value (LCV)


 

Engineering Chemistry: Unit IV: b. Combustion of Fuels : Tag: Engineering Chemistry : Dulong's formula with Example Solved Problems - Theoretical Calculation of Calorific Values


Engineering Chemistry: Unit IV: b. Combustion of Fuels



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